How many address lines are used in 4k memory
WebJul 5, 2015 · 2 Answers. To express in very easy terms, without any bus-multiplexing, the number of bits required to address a memory is the number of lines (address or data) … WebHow many address lines can be directly connected to each 4K RAM chip? Assume a 16Kx8 memory is designed using 4Kx1 RAM chips. How many address lines can be directly connected to each 4K RAM chip? Expert Answer 100% (5 ratings) log2 (4096 … View the full answer Previous question Next question
How many address lines are used in 4k memory
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WebAny memory size is given by = 2 K × m K = address line m = data line Eg: 1 KB memory = 2 10 × 8 Concept of decoder: For n × 2 n decoder no. of AND gates required are 2 n. Eg: 2:4 decoder, 4 AND gates are required. Analysis: Given For this memory 15 × 2 15 decoders required Since n = 15 So no. of AND gate are required = 2 15 Download Solution PDF WebHow many address lines are needed to select one of the memory chips? 32 MB is 2^5 so 5 address lines are needed to select one of the memory chips. Suppose a system has a byte-addressable memory size of 4GB. How many bits are required for each address? 4GB is 2^2 x 2^30 =232. Thus, 32 bits are required for each address.
Web2K byte memory or 4K X 8 , 4K byte memory which contains 4096 locations, where each location contains 8-bit data. Only one f the 4096 locations can be selected at a time. In general, to address a memory location out of 'N' memory locations, one would require at least 'n’bits of address i.e. 'n' address lines where WebNov 2, 2024 · That depends on the memory architecture of the system. if the memory chips are byte wide and not used to create a multibyte bus, 11 address bits are needed. if the memory chips are 32 bits wide, 9 address bits are needed (with the CPU internally selecting which of the 4 bytes it will use).
WebJul 6, 2015 · 1. An address line usually refers to a physical connection between a CPU/chipset and memory. They specify which address to access in the memory. So the task is to find out how many bits are required to pass the input number as an address. In your example, the input is 2 kilobytes = 2048 = 2^11, hence the answer 11. WebFeb 18, 2024 · How many address lines are required for 4k ROM? There is no difference: on a typical system RAM and ROM share the same address space, and each byte needs to …
WebDec 27, 2013 · The data outputs are kept separate to for the 32 lines required. Don't forget there are also control lines, usually a chip enable and a read line (usually active LOW) but …
WebNov 5, 2011 · How many address lines would you require to access 4K memory? You need 12 address lines to access 4K of memory. 212 = 4096. log2 (4096) = 12. How many … how many acres is jmuWebApr 9, 2024 · Assuming that the addressing is done at the byte level, show the format of main memory addresses using 8-way set-associative mapping. So here's what I have … high nitrogen fertilizer for lawns lowesWebApr 9, 2024 · A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory size that is cacheable is 1024 Mbits. Assuming that the addressing is done at the byte level, show the format of main memory addresses using 8-way set-associative mapping. high nitrogen on gcms 5977bhttp://www.ee.nmt.edu/~rison/ee231_fall10/hw/hw11_soln.pdf how many acres is heartland ranchWeb18K views, 1.1K likes, 389 loves, 1.4K comments, 1.2K shares, Facebook Watch Videos from American News Network: US lost the war on homeless Americans and in the Ukraine as Biden does not endorse... high nitrogen lawn fertilizer bunningsWebQuestion 1 How many address bits are needed to select all locations in a 256 x S memory? Question 2 Assume a 16Kx8 memory is designed using 4Kx1 RAM chips. How many … how many acres is kennywoodWebFeb 24, 2013 · I know for 1k we need 10 address lines. So for 2k it would 11. For 4k it would be 12. And for 8k, it should be 13. Is 13 correct answer? Zulfi. Papabravo Joined Feb 24, 2006 19,825 Feb 22, 2013 #2 Yes, and the formula is: ciel (log_2 (M)) where M is the size of the memory [in words or other addressable units] log_2 is the logarithm to the base 2 how many acres is harvard campus